This shows the $2$-chain $$ d_3(abcd) = bcd - acd + abd - abc = bcd + adc + abd + acb. $$ It consists of all the faces of the tetrahedron, oriented as indicated by the circular arrows.

If you focus on any one edge, you will see that the two adjacent circles rotate in opposite directions. Thus, in $d_2(d_3(abcd))$ the edge will appear twice, with opposite directions, which will cancel out. Because of this, we have $d_2(d_3(abcd))=0$.